Math, asked by kumarashima769, 8 hours ago

(27x³_343y³) numbers are divisible by (3x_7y)

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Answered by asajjadkhan817

0

3x³-7y³=(3x-2y) (3x²+3x×7y+7y²)

=(3x-2y)(9x²+21xy +49y²)ans

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