(27x³-8)by (3x-2) divide the following question
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(27x³-8) / 3x-2
27/3 x³-² (–8/–2)
9x – 4
27/3 x³-² (–8/–2)
9x – 4
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(27x^3-8) can be written in the form [(3x)^3-(2)^3].
So, [(3x)^3-(2^3] / 3x-2.
=>(3x-2) (3x^2+2^3-2×3x×2) / (3x-2)
So the result will be 9x^2-12x+8.
HOPE IT HELPS YOU... ☆☆☆
So, [(3x)^3-(2^3] / 3x-2.
=>(3x-2) (3x^2+2^3-2×3x×2) / (3x-2)
So the result will be 9x^2-12x+8.
HOPE IT HELPS YOU... ☆☆☆
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