Question

27x³+y³+64z³-36xyz plz help me​

Answer 1

Answer:

we know,

a^3+b^3+c^3-3abc

=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

27x^3+y^3+64z^3-36xyz

=(3x)^3+(y)^3+(4z)^3-3.3x.y.4z

=(3x+y+4z){(3x)^2+y^2+(4z)^2-3x.y-y.4z-4z.3x}

=(3x+y+4z)(9x^2+y^2+16z^2-3xy-4yz-12xz)

Answer 2

Answer:

(3)x³-8y³-27 - 18xy is y