Question

27y ^ 3 - 1/(27y ^ 3) - 6y + 2/(3y) * c * a * n The expression 27y3 be written as​

Answer 1

Answer:

STEP

1

:

Equation at the end of step 1

(((27 • (y3)) - 33y2) + 9y) - 1

STEP

2

:

Equation at the end of step

2

:

((33y3 - 33y2) + 9y) - 1

STEP

3

:

Checking for a perfect cube

3.1 27y3-27y2+9y-1 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 27y3-27y2+9y-1

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 9y-1

Group 2: 27y3-27y2

Pull out from each group separately :

Group 1: (9y-1) • (1)

Group 2: (y-1) • (27y2)

Answer 2

Answer:

I don't know but I try to solve.

I will asked my sir and then I reply with you