Question

28( ) 14 ( ) 32 ( ) 38 ( ) 46 = 54​

Answer 1

Answer:

(2a-1)2+(2b-1)2+(2c-1)2

=(2a-1+2b-1+2c-1)2

=(2(a+b+c)-3)2

So, we get equation

(2(a+b+c)-3)2=60

=>2(a+b+c)-3=30

=>2(a+b+c)-3=30

=>2(a+b+c)=33

33 being odd, it cannot be double of sum of natural numbers