Math, asked by rk9006508915, 4 months ago

28
24.
The true statement for the graph
of inequations 3.x + 2y s 6 and
6.r +4v > 20 is :
(A) Both graphs are disjoint
(B) Both do not contain origin
(C) Both contain point
(D) None of the above​

Answers

Answered by hussainhussian
6

Answer:

(A) Both graphs are disjoint

Step-by-step explanation:

The equations, corresponding to inequalities and are and . So the lines represented by these equations are parallel. Hence the graphs are disjoint.

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