Math, asked by uthara123, 2 days ago

28.28=2×8^(1÷2)×k^(1÷2) find the value of k​

Answers

Answered by ghost7890
2

Answer:

k = 1/2 or, k = – 1.

Step-by-step explanation:

follo.

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Answered by satyambardawaj
5

Since the given points are collinear, they do not form a</p><p></p><p>triangle, which means area of the triangle is Zero.</p><p></p><p>Area of a triangle with vertices (x1,y1) ; (x2,y2)  and (x3,y3)  is ∣∣∣∣2x1(y2−y3)+x2(y3−y1)+x3(y1−y2)∣∣∣∣</p><p></p><p>Hence, substituting the points (x1,y1)=(8,1) ; (x2,y2)=(k,−4)  and (x3,y3)=(2,−5)</p><p>the area formula, we get</p><p></p><p>∣∣∣∣28(−4+5)+k(−5−1)+2(1+4)∣∣∣∣ \

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