Chemistry, asked by salikm618, 1 month ago

28. A 0.001 M solution of Acetic acid is 5% ionised at 25 degree celsius. Calculate its dissociation constant. (1 Point) 0 2.63 x 10+5 0 2.63 x 10-5 O 2.63 x 10-4 0 2.63 x 104

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Answered by 06061981naresh

1

Answer:

25 degree Celsius × 0.001 ÷ 0.263 × 2.63 × 10-5×2.63×10-4×2.63×104

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