Question

28. A die is thrown once. Find the probability of getting
i) a Prime Number ii) a number lying between 2 and 6
iii) an odd number iv)multiple of 3




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Answer 1

Answer:

is attached

Step-by-step explanation:

I hope this helps u

Answer 2

Step-by-step explanation:

let A is the set of die thrown once

: A ={1,2,3,4,5,6}. therefore n(A)=6

to find

1) A prime Number

B is the Set Of Prime Number

: B={2,3,5}. therefore n(B)=3

therefore Probability of getting A Prime Number is equal to

P(B)=n(B)/n(A)

:. =3/6

=1/2

2) A number lying between 2 and 6

C is the set of numbers lying between 2 and 6

: C={3,4,5}. therefore n(C)=3

therefore Probability of getting a number lying between 2 and 6 is equal to

P(C)=n(C)/n(A)

:. =3/6

=1/2

3)an odd number

D is the Set Of an odd number

:D={1,3,5}. therefore n(D)=3

therefore Probability of getting an odd number is equal to

P(D)=n(D)/n(A)

:. =3/6

=1/2

4))multiple of 3

E is the set of an number multiple by 3

:E={3,6}. therefore n(E)=2

therefore Probability of getting an number multiple by 3 is equal to

P(E)=n(E)/n(A)

:. =2/6

=1/3