Question

28 A force of 50 N acting tangentially to a circle of radius 2
m. Its moment about diametrically opposite point will be
(a) 300 N·m
(b) 200 Nom
C) 400 Nm
(d) 100 N.m​

Answer 1

Answer:

b

Step-by-step explanation:

the answer is attached above I hope that this will help you

Answer 2

Step-by-step explanation:

Given:  $28A$ force of $50N$ and radius is $2m$

To find: Diametrically opposite point.

For calculating diametrically opposite point,

We know that the formula is $F$ × $Diameter$

The diameter of the circle is $2$ × r

⇒ $50N$ × $2$ × $2$

⇒ $50N$ × $4m$

⇒ $200Nm$

The answer is (b) $200Nm$.