Question

28. A particle is released from rest from a
tower of height 3h. The ratio of times to
fall equal heights 'h' i.e. t1:t2:t3 is
Ans. 10:4:3

Answer 1

Answer:

Time in falling first height h will be t1=T1=2g2h

Time in falling first height 2h will be T2=2g2(2h)

so the time in falling second h will be t2=T2−T1=2gh(24−22)

Time in falling in height 3h will be T3=2g2(3h)

so the time in falling third h will be t3=T3−(T1+T2)=2gh(26