28. A particle start moving from rest state along a straight line under the action of a constant force and travel distance x in first 5 seconds. The distance travelled by it in next five seconds will be (1) X (2) 2x (3) 3x (4) 4x
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Answer:
3X
Explanation:
S=ut + 0.5at²
given
u= 0
S= X in first 5 sec
X=0.5a5²
next five second
s10-s5= 0.5a(10)²-0.5a(5)²
10=2x5
10²=4x5²
s10-s5=4(0.5a5²)-(0.5a5²)
=4X-X
=3X
ans 3X
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