Question

28. A person distributes ten chocolates among five boys in a
certain ratio giving at least one chocolate to each boy. Boys
with the same number of chocolates team up resulting in two
teams and a single boy. The teams demand all chocolates from
the sole boy having the largest number of chocolates. Each
team gains two chocolates as a result. Find the ratio of the
chocolates lost by the single boy to the least number of
chocolates given out in the initial distribution.
(a) 1
(b) 2
(c) 3
(d) 4​

Answer 1

Answer:

18 chocolates

Step-by-step explanation:

x- number of boys

y- number of chocolates

If one chocolate is distributed, we have

y=x+8

If two chocolates distributed

y=2(x-1)

x+8=2(x-1)

x=10 boys, then y=18 chocolates