Math, asked by shruthishetty281, 6 months ago


28. A select group of 4 is to be formed from 8 men and
6 women in such a way that the group must have
at least 1 woman. In how many different ways can
it be done?
(Bank P.O., 2005)
(a) 364
(b) 728
(c) 931
(d) 1001
(e) None of these
ons are

Answers

Answered by lalitnit
0

Answer:

The combination are,

8C0*8C4 + 8C1*8C3 + 8C2*8C2 + 8C3*8C1

= 1*70 + 8*56 + 28*28 + 56*8

= 70 + 448 + 784 + 448

= 1750

Answered by dashdebabrat01
0

Step-by-step explanation:

The total number of people is 8+6 = 14

An easy way to calculate the number of ways of selecting atleast one woman is to calculate the opposite of it.

The total number of ways of selecting 4 people from a total of 14 is

14

C

4

=

1001

The number of ways of selecting a group of all men (and no women) is

8

C

4

=

70

Hence, the number of ways of selecting 4 people such that atleast one of them is a woman is

1001

70

=

931

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