Question

28
at time t given by f = fo1-4).where f, and
he
5
A particle moving along x-axis has acceleration f
are constants. The particle at t= 0 has zero
velocity. In the time interval between t= 0 and the 33
instant when f = 0, the particle's velocity (vx) is​

Answer 1

Givenf=f0​(1−Tt​)wheref0​andT=constantAtt=0v=0Whenf=0,than0=f0​(1−Tt​)T=t−−−−−−(1)weaccelerationf=Timefinal−initialvelocity​dtdv​=f0​(1−Tt​)∫dv=∫f0​(1−Tt​)dtv=f0​(t−2Tt2​)Fromequtaion1wegett=Tv=21​f0​T