Question

28 chocolates dived into 2 in such way that 6/5 is equal to 2/3 find the number of chochlates each get

Answer 1

Answer:

Let the total number of chocolates with

Let the total number of chocolates withRahil be x.

Let the total number of chocolates withRahil be x.No. of chocolates given to brother = x/3

Let the total number of chocolates withRahil be x.No. of chocolates given to brother = x/3No. of chocolates given to friend = x/6

Let the total number of chocolates withRahil be x.No. of chocolates given to brother = x/3No. of chocolates given to friend = x/6No. of chocolates remaining with Rahil

Let the total number of chocolates withRahil be x.No. of chocolates given to brother = x/3No. of chocolates given to friend = x/6No. of chocolates remaining with Rahil= 30

Let the total number of chocolates withRahil be x.No. of chocolates given to brother = x/3No. of chocolates given to friend = x/6No. of chocolates remaining with Rahil= 30x= x/3 + x/6 + 30→ - 30 = x/3 + x/6- X (Transposing 30

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposing

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6+30 = 3x/6

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6+30 = 3x/6→ 3x = 6* 30

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6+30 = 3x/6→ 3x = 6* 30→ 3x = 180

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6+30 = 3x/6→ 3x = 6* 30→ 3x = 180→X = 180/3

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6+30 = 3x/6→ 3x = 6* 30→ 3x = 180→X = 180/3→X = 60

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6+30 = 3x/6→ 3x = 6* 30→ 3x = 180→X = 180/3→X = 60Total no. of chocolates with Rahil = 60

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6+30 = 3x/6→ 3x = 6* 30→ 3x = 180→X = 180/3→X = 60Total no. of chocolates with Rahil = 60No. of chocolates given to brother = x/3

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6+30 = 3x/6→ 3x = 6* 30→ 3x = 180→X = 180/3→X = 60Total no. of chocolates with Rahil = 60No. of chocolates given to brother = x/3= 60/3 = 20

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6+30 = 3x/6→ 3x = 6* 30→ 3x = 180→X = 180/3→X = 60Total no. of chocolates with Rahil = 60No. of chocolates given to brother = x/3= 60/3 = 20No. of chocolates given to freind = x/6 =

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6+30 = 3x/6→ 3x = 6* 30→ 3x = 180→X = 180/3→X = 60Total no. of chocolates with Rahil = 60No. of chocolates given to brother = x/3= 60/3 = 20No. of chocolates given to freind = x/6 =60/6 = 10

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6+30 = 3x/6→ 3x = 6* 30→ 3x = 180→X = 180/3→X = 60Total no. of chocolates with Rahil = 60No. of chocolates given to brother = x/3= 60/3 = 20No. of chocolates given to freind = x/6 =60/6 = 100.0 (0)

Answer 2

Answer:

Let the total number of chocolates withRahil be x.

Let the total number of chocolates withRahil be x.No. of chocolates given to brother = x/3

Let the total number of chocolates withRahil be x.No. of chocolates given to brother = x/3No. of chocolates given to friend = x/6

Let the total number of chocolates withRahil be x.No. of chocolates given to brother = x/3No. of chocolates given to friend = x/6No. of chocolates remaining with Rahil= 30

Let the total number of chocolates withRahil be x.No. of chocolates given to brother = x/3No. of chocolates given to friend = x/6No. of chocolates remaining with Rahil= 30x= x/3 + x/6 + 30→ - 30 = x/3 + x/6- X (Transposing 30

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposing

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6+30 = 3x/6

- 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6+30 = 3x/6→ 3x = 6* 30→ 3x = 180

30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6+30 = 3x/6→ 3x = 6* 30→ 3x = 180→X = 180/3→X = 60

x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6+30 = 3x/6→ 3x = 6* 30→ 3x = 180→X = 180/3→X = 60Total no. of chocolates with Rahil = 60

x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6+30 = 3x/6→ 3x = 6* 30→ 3x = 180→X = 180/3→X = 60Total no. of chocolates with Rahil = 60No. of chocolates given to brother = x/3= 60/3 = 20

x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6+30 = 3x/6→ 3x = 6* 30→ 3x = 180→X = 180/3→X = 60Total no. of chocolates with Rahil = 60No. of chocolates given to brother = x/3= 60/3 = 20No. of chocolates given to freind = x/6 =60/6 = 10

→ - 30 = x/3 + x/6- X (Transposing 30to LHS, becomes - 30 and transposingx to RHS, becomes - x)→ 30 = -x/3 - X/6 + x→ 30 = - 2x/6 - X/6 + 6x/6+30 = 3x/6→ 3x = 6* 30→ 3x = 180→X = 180/3→X = 60Total no. of chocolates with Rahil = 60No. of chocolates given to brother = x/3= 60/3 = 20No. of chocolates given to freind = x/6 =60/6 = 100.

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