Question

28. Factorise: x2 + 1/x2+ 2x-2/x​

Answer 1

Step-by-step explanation:

Rearranging, (x^2+1/x^2) -2(x+1/x) +2 = 0

Formula : x^2+1/x^2 = (x+1/x)^2 - 2

(x+1/x)^2-2-2(x+1/x) +2 = 0

(x+1/x)^2-2(x+1/x) = 0

(x+1/x)(x+1/x) - 2(x+1/x) = 0

(x+1/x)[(x+1/x)-2] = 0

x+1/x = 0

and (x+1/x)-2 = 0

x+1/x = 2

Therefore, the roots are 0 and 2