Math, asked by lovekush98, 5 months ago

28. Find
18. Sudesh is twice as old as Seema. If six years is subtracted from Seema's age and four
years are added to Sudesh's age, Sudesh will be four times Seema's age. How old were
they three years ago?​

Answers

Answered by preetrandhawa33
4

Answer:

Let seema's age be 'x' years

and sudesh's age be 'y' years

⇒y=2x

⇒4(x−6)=(y+4)

⇒4(x−6)=2(2x+4)

⇒4x−2x=2x+4

⇒2x=28

Rightarrowx=14years

y=2x=28years

3 years ago seema was 11 years & sudesh was 25 years.

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