Question

28. Find the number ofterms in the first AP :3,6,9....111
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Answer 1

• The given sequence is an A.P. with first term a=3 and common difference d=3. Let there be n terms in the given sequence. Then,
• nth term=111
• a+(n−1)d=111
• 3+(n−1)×3=111
• n=37
• Thus, the given sequence contains 37 terms.