Math, asked by allababysirisha27505, 7 months ago

28. Find the value of
2( sin^6teta+cos^6teta)-3(sin^4teta+cos^4teta)​

Answers

Answered by AmeyaBorghare
0

Answer:

sinolstan since Stan sinn

Answered by GargVarnit
1

Answer:

0

Step-by-step explanation:

ANSWER

=2(sin 6 θ+cos 6θ)−3(sin 4 θ+cos 4 θ)+1

=2{(sin 2 θ+cos 2 θ) 3 −3sin 2 θcos 2 θ(sin 2 θ+cos 2 θ)}−3(sin 2 θ+cos 2 θ) 2 −2(sin 2 θcos 2 θ)}+1

We know, [sin²x+cos²x=1]

=2{1−3sin 2 θcos2θ}−3{1−2sin 2θcos 2θ}+1

=2−6sin 2 θcos 2 θ−3+6sin 2 θcos 2 θ+1=0

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