28. Find the value of
2( sin^6teta+cos^6teta)-3(sin^4teta+cos^4teta)
Answers
Answered by
0
Answer:
sinolstan since Stan sinn
Answered by
1
Answer:
0
Step-by-step explanation:
ANSWER
=2(sin 6 θ+cos 6θ)−3(sin 4 θ+cos 4 θ)+1
=2{(sin 2 θ+cos 2 θ) 3 −3sin 2 θcos 2 θ(sin 2 θ+cos 2 θ)}−3(sin 2 θ+cos 2 θ) 2 −2(sin 2 θcos 2 θ)}+1
We know, [sin²x+cos²x=1]
=2{1−3sin 2 θcos2θ}−3{1−2sin 2θcos 2θ}+1
=2−6sin 2 θcos 2 θ−3+6sin 2 θcos 2 θ+1=0
Similar questions