Question

28. Find the value of a & b
$5 + 2 \sqrt{3} \div 7 + 4 \sqrt{3} = a + b \sqrt{3}$
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Answer 1

Answer:

0

Step-by-step explanation:

mera mume le aur answer aa jayega

Answer 2

Step-by-step explanation:

5 + 2 \sqrt{3} \div 7 + 4 \sqrt{3}5+23÷7+43

Rationalise the denominator...

(5 + 2 \sqrt{3} )(7 - 4 \sqrt{3} ) \div (7 + 4 \sqrt{3} )(7 - 4 \sqrt{3})(5+23)(7−43)÷(7+43)(7−43)

(35 - 20 \sqrt{3} + 14 \sqrt{3} - 24) \div (49 - 48)(35−203+143−24)÷(49−48)

(11 - 6 \sqrt{3} ) \div 1(11−63)÷1

11 - 6 \sqrt{3}11−63

Now compare it with

a - b \sqrt{3} = 11 - 6 \sqrt{3}a−b3=11−63

So a = 11 and b = 6

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