Question

28 g nitrogen reacts with 4g hydrogen to form ammonia.Identify the limiting reagent and calculate the mass of unreacted substance.​

Answer 1

Answer:

Explanation:

equivalent of nitrogen = moles*f = 6

equivalent of hydrogen = moles*f=4

equivalent of ammonia  =equivalent of hydrogen = 4

moles*f=4

moles = 2

mass of ammonia formed = 34 gm

equivalent of nitrogen unreacted = 2

moles*6 = 2

moles = 1/3

mass unreacted = 28/3  

alter method  

mole/sc for n2 = 1

mole/sc for h2 = 2/3

moles of unreacted substance = 1-2/3 = 1/3

mass = 28/3 gm