Question

28 gram of Nitrogen and 6 gram of hydrogen were mixed at equilibrium 17 gram Ammonia was produced the weight of Nitrogen and hydrogen at equilibrium are respectively​

Answer 1

Answer:

yes nnsjjebknejeneksnnwmksjmjnamamem

Answer 2

Answer:

28g of N2 and 6g of H2 were mixed.

molar mass of N2 = 28 g/mol

so, number of mole of N2 is mixed = 28/28 = 1

molar mass of H2 = 2 g/mol

so, number of mole of H2 is mixed = 6/2 = 3

see reaction,

N2 + 3H2 => 2NH3

at equilibrium ,

number of mole of N2 = 1 - x

number of mole of H2 = 3 - 3x

number of mole of NH3 = 2x

so, mass of NH3 is produced = mole × molar mass of NH3

= 2x × (14 +3) = 34x

given, mass = 17g = 34x

so, x = 0.5

so, at equilibrium,

number of mole of N2 = 1 - 0.5 = 0.5

hence,mass of N2 = 0.5 × 28 = 14g

number of mole of H2 = 3 - 3 × 0.5

= 1.5

hence, mass of H2 = 1.5 × 2 = 3g

hence, answer is 14g, 3g

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