Question

28. I am 8 times as old as you were when I was old as you are, said
a man to his son. What are the ages of the father and the son (in
years)?
(a) 47, 28
(b) 49,26
(c) 48, 27
(d) 52, 23​

Answer 1

Answer:

c

Step-by-step explanation:

Let 'x' be the present age of the man,

Let 'y' be the present age of the son,

Given that man was 8 times as old as when the man was as old as son at present

=> before x - y years

Man's Age = y years

Sons Age = y - (x - y)

= 2y - x

Given x = 8(2y-x)

=> 16y = 9x.

Also given Sum of their present ages is 75 years

=> x + y = 75

=> 9x + 9y = 75*9 = 675

=> 16y + 9y = 675

=> y = 27 and x = 48.

Hope, it helped !