Question

28. If alpa and beta are zero of polynomials x2 + 2x – 15, find quadratic eq. whose zeroes are 1÷alpa² and 1÷beta²​

Answer 1

Answer:

hshdjiaia hhg jjj h hh j h

Answer 2

Answer:

1/25;1/9

Step-by-step explanation:

${x}^{2} + 2x - 15 = 0 \\ {x}^{2} + 5x - 3x - 15 = 0 \\ x(x + 5) - 3(x + 5) = 0 \\ (x + 5)(x - 3) = 0 \\ x + 5 = 0 \\ x = - 5 \\ x - 3 = 0 \\ x = 3 \\ here \: \alpha = - 5 \: and \: \beta = 3 \\ 1 \div \alpha {}^{2} = 1 \div ( { - 5)}^{2} = \frac{1}{25} \\ \\ 1 \div { \beta }^{2} = 1 \div {3}^{2} = \frac{1}{9}$