28. If sin a.sin ß-cosa.cosB =1, show that tan a+tan B=0.
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Hey Buddy here's ur answer
sinAsinB - cosAcosB = 1 <--- given
cosAcosB - sinAsinB = -1 <--- multiplies both sides by -1
cos(A+B) = -1 <--- angle addition formula for cosine
A+B is an odd multiple of pi <--- cosine function is -1 at 180=pi, 540 = 3*pi, 900=*5*pi, etc
sin(A+B)=0 <-- sine function is zero at odd multiples of pi
sinAcosB + sinBcosA = 0 <--- angle addition formula for sine
sinA/cosA + sinB/cosB = 0 <--- divides both sides by cosA*cosB
tanA + tanB = 0 <--- tan = sin/cos
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b cos to the question of a little bit about me
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