Question

28. If sin a.sin ß-cosa.cosB =1, show that tan a+tan B=0.​

Answer 1

Answer:

Hey Buddy here's ur answer

sinAsinB - cosAcosB = 1 <--- given

cosAcosB - sinAsinB = -1 <--- multiplies both sides by -1

cos(A+B) = -1 <--- angle addition formula for cosine

A+B is an odd multiple of pi <--- cosine function is -1 at 180=pi, 540 = 3*pi, 900=*5*pi, etc

sin(A+B)=0 <-- sine function is zero at odd multiples of pi

sinAcosB + sinBcosA = 0 <--- angle addition formula for sine

sinA/cosA + sinB/cosB = 0 <--- divides both sides by cosA*cosB

tanA + tanB = 0 <--- tan = sin/cos

Answer 2

Answer:

b cos to the question of a little bit about me