Math, asked by sd245575, 1 month ago

28. If x =
2a + 3b + 2a - 36
2a + 36 - 2a - 36
prove that 36x2 - 4ax + 36 = 0
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Answers

Answered by arshdeep9643
2

Answer:

If x =

2a + 3b + 2a - 36

2a + 36 - 2a - 36

prove that 36x2 - 4ax + 36 = 0

Step-by-step explanation:

x=

2a+3b

2a−3b

2a+3b

+

2a−3b

Rationalizing

⇒x=

2a+3b

2a−3b

2a+3b

+

2a−3b

×

2a+3b

+

2a−3b

2a+3b

+

2a−3b

⇒x=

2a+3b−2a+3b

2a+3b+2a−3b−2

4a

2

−9b

2

⇒x=

36

2a−

4a

2

−9b

2

⇒36x−2a=−

4a

2

−9b

2

squaring

⇒9b

2

x

2

+4a

2

−12abc=4a

2

−9b

2

⇒96

2

x

2

+96

2

−12abx=0

divide by 3b

⇒36x

2

−4ax+36=0

Answered by Anonymous
1

Step-by-step explanation:

x=

2a+3b

2a−3b

2a+3b

+

2a−3b

Rationalizing

⇒x=

2a+3b

2a−3b

2a+3b

+

2a−3b

×

2a+3b

+

2a−3b

2a+3b

+

2a−3b

⇒x=

2a+3b−2a+3b

2a+3b+2a−3b−2

4a

2

−9b

2

⇒x=

36

2a−

4a

2

−9b

2

⇒36x−2a=−

4a

2

−9b

2

squaring

⇒9b

2

x

2

+4a

2

−12abc=4a

2

−9b

2

⇒96

2

x

2

+96

2

−12abx=0

divide by 3b

⇒36x

2

−4ax+36=0

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