Question

28. Line L is the bisector of an angle LA and B is any point on L. BP and BQ are perpendicular
from B to the arms of LA. Show that:
l
A A
Р
a) ΔΑΡΒ2 ΔΑQB
b) BP = BQ​

Answer 1

In △APB and △AQB

∠APB=∠AQB (Each 90° )

∠PAB=∠QAB (l is the angle bisector of ∠A)

AB=AB (Common)

∴△APB≅△AQB (By AAS congruence rule)

∴BP=BQ (By CPCT)

It can be said that B is equidistant from the arms of ∠A.