Math, asked by rajwinderkaur10777, 8 months ago

28. Mrs. Jain is 27 years older than her daughter Nilu. After 8 years she will be twice as old
as Nilu. Find their present ages.​

Answers

Answered by SashikalaAppalla
1

Step-by-step explanation:

hope the above answer will help you

Attachments:
Answered by Anonymous
14

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\huge\red{\underline{{\bf Question : }}}

✦ Mrs Jain is 27 years older than her daughter Nilu. After 8 years she will be twice as old as Nilu. Find their present ages?

\huge\red{\underline{{\bf Answer : }}}

\bf\large{\underline\blue{Given:}}

➛ Mrs. Jain is 27 years older than her daughter Nilu.

➛ After 8 years she will be twice as old

as Nilu.

\bf\large{\underline\green{To Find:}}

➛ Find the present ages of Nilu and Mrs. Jain.

\bf\large{\underline\orange{Solution:}}

⟶ Let the present age of Nilu be x years

⟶ Therefore the present age of Nilu's mother = ( x + 27 ) years.

▪️So, after 8 years,

⟶ Nilu's age = ( x + 8 )

⟶ Mrs. Jain's age = ( x + 27 + 8 ) = ( x + 35 ) years.

\sf\pink{⟹ \: x + 35 = 2(x + 8)}

▪️Expanding the brackets, we get :

\sf\pink{⟹ \: x + 35 = 2x + 16}

▪️Transposing x to RHS and 16 to LHS, we get :

\sf\pink{⟹ \: 35 - 16 = 2x - x}

 \sf\pink{⟹ \: x = 19}

⟶ So, the present age of Nilu =

{\boxed{{\bf{x = 19 \: years.}}}}

⟶ And the present age of Nilu's mother that is Mrs . Jain =

{\boxed{{\bf{x + 27 = 19 + 27 = 46 \: years.}}}}

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