Question

28% of a group are married. 40% of the people are women. 60% of men are unmarried. What is the ratio of the married men and unmarried women?

Answer 1

Answer:

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Answer 2

Answer:

2 : 3

Step-by-step explanation:

Let x be the total number of persons,

If 40% are women,

Women = 40% of x = 0.4x,

Men = (100-40)% of x = 60% of x = 0.6x,

Now, 60% men are unmarried,

So, married men = (100-60)% of total men = 40% of 0.6x = 0.4(0.6x) = 0.24x,

Also, 28% of a group are married,

unmarried persons = (100-28)% of x = 72% of x = 0.72x,

Thus, unmarried women = unmarried persons - unmarried men = 0.72x - 60% of total men

= 0.72x - 0.6(0.6x)

= 0.72x - 0.36x

= 0.36x

Hence, the ratio of married men and unmarried women = $\frac{0.24x}{0.36x}=\frac{24}{36}=\frac{2}{3}$