Math, asked by divikatiyar0435, 1 year ago

28.Prove that
sin0/(sec 0+tan 0-1)+cos0/ (cosec 0+ cot 0-1)=1​

Answers

Answered by Anonymous
3

Answer:

hey mate please refer to the attachment

Attachments:
Answered by Riteshkp2005
1

Step-by-step explanation:

sinO/(1/cosO+sinO/cosO–1) + cosO/(1/sinO+cosO/sinO-1)

=sinO/ (1+sinO-cosO)/cosO. + cosO/ (1+cosO-sinO)/sinO

=sinOcosO/(1+sinO-cosO). + sinOcosO/(1-sinO+cosO)

=sinOcosO(1-sinO+cosO) + sinOcosO(1+sinO-cosO) / (1+sinO-cosO)*(1-sinO+cosO)

=sinOcosO(1-sinO+cosO + 1+sinO-cosO) / {(1)^2 – (sinO-cosO)^2}

=sinOcosO(2) / {1 – (sin^2+ cos^2 – 2sinOcosO)}

=2sinOcosO / {1 – (1 – 2sinOcosO)}

=2sinOcosO / {1-1+2sinOcosO}

=2sinOcosO / 2sinOcosO

=1=RHS. (proved)

please follow me if it helped you:;☺)

RKP

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