Question

28 root 3 - 10 root 3

Answer 1

Answer:

First take a^2= 28 - 10*3^(1/2)

=> 5^2 + (- 3^1/2) ^2+ 2 . 5.(-3^1/2) {{ of form x^2 + y^2 + 2.x.y = (x+y)^2}}

=> (5 - 3^(1/2)) ^2

That gives a = 5 - 3^1/2

Now let b^2 = 1/(7 + 4.3^1/2)

Multiply by 7 - 4.3^1/2 on both numerator and denominator

gives, b^2 = 7 - 4.3^1/2

=> (2)^2 + (-3^1/2)^2 + 2.(2).(-3^1/2)

{{ of form x^2 + y^2 + 2.x.y = (x+y)^2}}So this gives

b = 2 - 3^1/2

You asked the value of a- b = 5 - 2 = 3

Answer 2

Step-by-step explanation:

28 root 3-10root3=3-10+2