Math, asked by bhupeshkaushik830723, 5 months ago

28.Solve the below linear equation:1/5(3t-2) -1/3(2t+3) =2/3 -t

3 points

(A) 14/31

(B) 31/21

(C) 31/14

(D) 13/31

Answers

Answered by kirandoshi1997
2

Answer:

1/5*(3t-2) - 1/3*(2t+3)=2/3 -t

3t-2/5 - 2t+3/3=2/3 -t

(9t-6) - (10t+15)/15 = 2-3t / 3

9t-6-10t-15/15 = 2-3t /3

-t-21/15 = 2-3t/3

-3t - 63 = 30-45t

45t-3t = 30+63

42t= 93

t= 93/42

t= 31/14

Similar questions