Question

28. The atomic transition gives rise to the radiation of
frequency (104 MHz). The change in energy per mole of
atoms taking place would be :
(a) 3.99 x 10-6 J (b) 3.99 J
(c) 6.62 x 10-24 J (d) 6.62 x 10-30 J

Answer 1

Answer:

I think so the question is wrong

Answer 2

Answer:

b) 3.99J

Explanation:

Frequency after atomic transition = 104MHz (Given)

Energy of one photon is given by the expression E = hV

where where, h is the Plancks constant = 6.626 x 10-34 and

V is the frequency of radiation = 104MHz.

Therefore, as per the formula -

E = Nhv

= 6.023 × 10`23× 6.626 ×10−34 × 10`4 × 10`6

= 3.99J

Therefore, The change in energy per mole of  atoms taking place will be 3.99J.