28. The circumference of second orbit of H-atom
wavelength of electron is 5 x 10-9m
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Circumference =2 pi r......(1)
r=2×2(0.529)×10^-10 m
r=2.116×10^-10
Put in eq 1 and you will get the answer
r=2×2(0.529)×10^-10 m
r=2.116×10^-10
Put in eq 1 and you will get the answer
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