Question

28. The deflection of an electron moving in
transverse electric field is
(2 Points)
6=1/2 D^' 1/d V/V_A
6=1/2 D^' 1/d 1/V
6=1/2 D^' 1/d V_A/V
6= D^' 1/d V/V_A​

Answer 1

Explanation:

The word electrostatic means the strength and the direction of the field ... D = deflection of the electron beam on the screen in the Y direction. ... electrostatic-deflection-plate-equation-1.

Answer 2

1. Electrostatic deflection $(D)$ is the deflection of an electron beam generated by an electrostatic field.

2. The deflecting force no longer acts on the electron when it escapes the electric field zone, and the electron travels in a straight line beyond the plates, striking the fluorescent screen.

3. The electron moves with a velocity $v$ in this region, which is the product of $v_{0}$ and $v_{y}$.

$v=\sqrt{v_{0}^{2}+v_{y}^{2} }$

4. If the electron's initial velocity, $v_{0}$ was achieved by passing it through voltage,$V_{A}$ then,

$v_{0}=\sqrt{\frac{2eV_{A}}{m} }$

$D=\frac{L\times l\times V}{2d\times V_{A}}$

Thus, electrostatic deflection $(D)$ is directly proportional to deflecting voltage $V$ and inversely proportional to accelerating voltage $V_{A}$.

Note: There is some error in the question.