28. The enthalpy waloes needed to break the two-OH bonds of H2O molecule is given below: H-DE-> High-CHỈg kh=502 kenolOH{g)> H(8) OHg); A.Hz=427 kmori) Calculate the average bond enthalpy for H2O molecule.1) Why are the enthalpy values needed to break the two-OH bonds of H2O molecules are different?111) Bond enthalpies for Ny and O2 bonds are 946 kl mor and 498 kt mol-1 respectively. Whichmolecule would have stronger bond
Answers
Answered by
1
Answer:
Search on Google I hope you found your answer.
Similar questions