Question

28.The position of a particle is 3 points
given by r =( 3t 1^- 2t^2jA+ 4K^
)m.Where t is in seconds, ris
in metres and the coefficients
have the proper units. (a) Find
the velocity v and acceleration
a of the particle?(b) What is
the magnitude of velocity of
the particle at t = 2.0 s?
O
(a) V = 3 i^ - 4 tj^ m/s a = - 4 ja
m/s^2, (b)(a) V (t =2s) = =V73 m/s
(a) V = 3 i^ + 4 t ja m/s a = 4 ja
m/s^2, (b)(a) V (t =2s) = =V73 m/s
O
(a) V = 3 i^ - 2 tj^ m/s a = -2 ja
m/s^2, (b)(a) V (t =2s) = =V53 m/s
(a) V = 3 i^ - 4 tj^ m/s a = -2 ja
m/s^2, (b)(a) V (t =2s) = =V37 m/s​

Answer 1

Answer:

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