Question

28. The ratio of the displacement of a freely falling body in
the last second to the total displacement is 11/36. The
time of travel is
1) 48 2)5 s 3) 6 S
4) 7 S​

Answer 1

Answer:

Suppose the flight is of time t then height fallen in time t will be H=

2

1

gt

2

And the height fallen in time t−1 second will be h=

2

1

g(t−1)

2

so the displacement of last second will be H−h=

2

g

(t

2

−t

2

−1+2t)

given that

H

H−h

=

36

11

so we have

t

2

2t−1

=

36

11

solving above equation we get t=6second

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