Question

28) The sum and the difference of the reciprocals of the ages of Aishwarya and her
daughter Aaradhya is
and -
respectively. Find their ages.​

Answer 1

Step-by-step explanation:

can u pls send the values

Answer 2

The age of aishwarya is 40 years and her daughter age is 10 years

Step-by-step explanation:

let her daughter age be x and the reciprocal of her age is $\frac{1}{x}$

let Aishwarya  age be y and the reciprocal of her age is $\frac{1}{y}$

then according to the question

$\frac{1}{x} +\frac{1}{y}= \frac{5}{40}$..(1)

$\frac{1}{x} -\frac{1}{y}= \frac{3}{40}$..(2)

solving 1 and 2 we get

let

$\frac{1}{x} =u \\ \frac{1}{y} =v$

$u+v = \frac{5}{40}\\\\u-v =\frac{3}{40}$

$2u = \frac{8}{40}\\\\u = \frac{1}{10}\\\\u= \frac{1}{x}=x= 10$

therefore

$v= \frac{1}{40}\\\\ v = \frac{1}{y}= y = 40$

hence , The age of aishwarya is 40 years and her daughter age is 10 years

#Learn more:

Aishwarya is five times her cousin's age. 12 years hence, she will be twice her cousin's

age. Find Aishwarya's and her cousin's ages.​

https://brainly.in/question/13817203