28) The sum and the difference of the reciprocals of the ages of Aishwarya and her daughter Aaradhya is 5/40 and3/40 to respectively. Find their ages.
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Let the ages be x-Aaradhya and y-Aishwarya
so 1/x+1/y=5/40
1/x-1/y=3/40 [x is smaller than y so 1/x will be greater than 1/y]
let 1/x=u and 1/y=v then after cross multiplying-
40u+40v=5--------i
40u-40v=3---------ii
so 80u=8
u=1/10
substitute in i
40*1/10+40v=5
40v=5-4=1
v=1/40
since 1/x=u and 1/y=v
x=10 and y=40
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