Question

28. The sum of all two digit positive numbers
which when divided by 7 yield 2 or 5 as
remainder is
1) 1256 2) 1465 3) 1365 4) 1356​

Answer 1

Answer:

Step-by-step explanation:

S1= (6+23+........93 s1=n/2(2a+n-1)d

S1=12/2(16+93)

S1=6×109

S1= 654

S2=12+19.........96

S2=13/2(12+96)

S2=13×108/2

S2=13×54

S2=702

Then total sum is,

Sum=s1+s2

Sum=654+702

Sum=1356