Math, asked by Apasas, 11 months ago

28. Two partners Abdul and Mahesh together lend Rs 1,68,200 at an interest rate of 5%, interest being
reckoned annually. Abdul lends for 3 years to a person while Mahesh lends for 5 years to another
person. The amounts they receive are equal. Find the shares of the two partners in the sum lent.​

Answers

Answered by badcaptain69
9

Answer:

Assume  shares of Abdul x and  Mahesha's share 168200-x.

We use the formula for Amount A = PNR/100, where P = principle, n = number of years the principle is invested/lent, and R = rate of interest.

Then Abdula Amount  A1 = x (1 +  (3*5/100))

Mahesha's Amount = A2 = (168200-x)(1  + (5* 5/100)).

Given that A1  =  A2,   x (1 +  (3*5/100))   =  (168200-x)(1  + (5* 5/100))..

We take x's to left and known values to right side:

x{ 1.15 + 1.25} =  168200 * 1.25

--> x = 168200 * 1.25/2.4

--> x = 87604.17 is Abdul's share

Mahesha's share =  168200-x  =  80595.83.

Abdul gets an amonut  = P+PNR/100 = P(1  + NR/100) = 87604.17 * 1.15 = 100744.79

Mahesh gets an Amount = P+PNR/100 = P(1  + NR/100) = 80595.83 * 1.25 = 100744.79

Hope this helps.

Answered by aloksingh860163
6

Answer:

Abdul's share = 88200

Mahesh Share = 80000

Step-by-step explanation:

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