Question

28. Two partners Abdul and Mahesh together lend Rs 1,68,200 at an interest rate of 5%, interest being
reckoned annually. Abdul lends for 3 years to a person while Mahesh lends for 5 years to another
person. The amounts they receive are equal. Find the shares of the two partners in the sum lent.​

Answer 1

Answer:

88200, 80,000

Step-by-step explanation:

let A lend x & then M lend (168200-x)

x(1+ 5/100)^3 = (168200-x)( 1+ 5/100)^5

x/(168200- x) = (1+ 5/100)^2

x/(168200-x) = 441/400

841x = 168200×441 => x = Rs 88200

shares of each A (x = 88200) &

M = 168200-88,200 = Rs 80,000

Answer 2

Answer:

Abdul=88200,Mahesh=80000

Explanation:

For Abdul,

Let the principal be P

Time= 3 years

Rate= 5%p.a

For Mahesh,

Principal= (168200-P)

Time = 5 years

Rate =5%p.a

A/Q,

P(1+R/100)^T=(168200-P)(1+R/100)^T

P(1+5/100)³=(168200-P)(1+5/100)⁵

P=(168200-P)(1+5/100)²

P/(168200-P)=(1+5/100)²

P/(168200-P)=(1+1/20)²

P/(168200-P)=(20+1/20)²

P/(168200-P)=(21/20)²

P/(168200-P)=(21*21/20*20)

P/(168200-P)=441/400

P*400=441(168200-P)

400P=74176200-441P

400P+441P=74176200

841P=74176200

P=74176200/841

P=88200

Therefore,

Abdul =88200

Mahesh=(168200-88200)

=88000