28. Two resistors when connected in series, their effective resistance is 9 ohm. Their effective resistance become 2ohm when they are connected in parallel. Find the value of the resistors.
Answers
Given: Two resistors when connected in series, their effective resistance is 9 ohm. Their effective resistance become 2ohm when they are connected in parallel.
Need to Find : Value of the Resistors
Let the value of resistors be x & y respectively
When these resistors connected in series the effective resistance is 9 ohm
↠ x + y = 9 ------------------(i)
Now,
when these resistors connected in parallel their effective resistance is 2 ohm
↠ 1/x + 1/y = 1/2
↠ x + y/xy = 1/2 -----------------(ii)
On substituting the equation (i) into equation (ii) we get
↠ 9/xy = 1/2
↠ 18 = xy
↠ 18/y = x ----------(iii)
Now, substituting equation (iii) in equation (i) we get
↠ 18/y + y = 9
↠ y² + 18 = 9y
↠ y² - 9y + 18 = 0
↠ y² - 6y - 3y + 18 = 0
↠ y ( y-6) + 3 ( y - 6 ) = 0
↠( y + 3) ( y-6) = 0
↠ y = -3 or y = 6
Since , resistance can't be negative .
So , y = 6
On substituting the value of y = 6 in equation (i) we get
↠ x + 6 = 9
↠ x = 9-6
↠ x = 3
- Hence, the value of the resistors are 3 & 6 ohm respectively .
Information provided with us༄
- Two resistors when connected in series, their effective resistance is 9 ohm.
- Their effective resistance become 2 ohm when they are connected in parallel.
What we have to calculate ༄
- The required value of the resistor
Assumption ༄
Consider the two resistance be
and
respectively
Now ༄
Or
So ༄
Therefore༄