28.Using quadratic formela, solve the following quadratic equation for x: P'a(p'-q-q0)
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Answers
Answer:
(1) 0 and 4
Sum of roots = 0 + 4 = 4
Product of roots = 0 × 4 = 0
The general form of the quadratic equation is x2−(Sum of roots)x+Product of roots=0
So, the quadratic equation obtained is x2−4x+0=0
⇒x2−4x=0⇒x(x−4)=0
(2) 3 and –10
Sum of roots = 3 + (–10) = −7
Product of roots = 3 × –10 = –30
The general form of the quadratic equation is x2−(Sum of roots)x+Product of roots=0
So, the quadratic equation obtained is x2−(−7)x+(−30)=0
x2+7x−30=0
(3) 12,−12
Sum of roots = 12+(−12)=0
Product of roots = 12×(−12)=−14
The general form of the quadratic equation is x2−(Sum of roots)x+Product of roots=0
So, the quadratic equation obtained is x2−(0)x+(−14)=0
⇒x2−14=0
(4) 2−5–√,2+5–√
Sum of roots = 2−5–√+2+5–√=4
Product of roots = (2−5–√)(2+5–√)=4−5=−1
The general form of the quadratic equation is x2−(Sum of roots)x+Product of roots=0
So, the quadratic equation obtained is x2−(4)x+(−1)=0
⇒x2−4x−1=0
Answer:
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