28. x² + 6x – (a² + 2a - 8) = 0
Solve and it by applying quadratic formula
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x = -(a+4) Or x = (a-2)
Step-by-step explanation:
Given quadratic equation:
x²+6x-(a²+2a-8)=0
=> x²+6x-(a²+4a-2a-8)=0
=> x²+6x-[a(a+4)-2(a+4)]=0
=> x²+6x-(a+4)(a-2)=0
Splitting the middle term,we get
=>x²+(a+4)x-(a-2)x-(a+4)(a-2)=0
=> x[x+(a+4)]-(a-2)[x+(a+4)]=0
=> [x+(a+4)][x-(a-2)]=0
=> x+(a+4)=0 Or x-(a-2)=0
=> x = -(a+4) Or x = (a-2)
Therefore,
x = -(a+4) Or x = (a-2)
quadratic formula cannot be applied here..
D = b^2-4ac
x = -b+/-√D. \ 2a
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