Question

280 ml of h2o2 reacts completely with 15.8g of KMno4 in acidic medium ,then the volume strength of h2o2​

Answer 1

Answer:

In alkaline medium, hydrogen peroxide reacts with KMnO

4

giving manganese dioxide.

2KMnO

4

+3H

2

O

2

→2MnO

2

+3O

2

+2KOH+4H

2

O

Explanation:

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Answer 2

Answer: Volume strength of H₂O₂=10

Explanation:

We use the law of equivalence here,

No. of gram equivalence of H₂O₂= No. of gram equivalence of KMnO₄

No. of gram equivalents = Normality × Volume in litres

Here, No. of milli equivalents of H₂O₂=No. of milliequivalents of KMnO₄

Let the volume strength of H₂O₂ be V,

$280×(V÷5.6)=15.8÷(158÷5)×1000$

[280×(V÷5.6)] =[ 15.8÷(158÷5)×1000]

$V=10$