280 mL of sulphur vapour at STP weighs 3.2 g. The atomicity of sulphur vapour molecule is
(Given: Atomic mass of S - 32)
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280ml of sulphur vapour at ntp weigh 3.2g. The molecular formula of the sulphur vapour is?
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Since, Density of a gas = Mass/ volume
=) 3.2gm/280 ml
Molecular mass = molar vol. × density
Since, molar volume at N.T.P = 22.4L =) 22.4×1000ml
So, molecular mass= 22.4 × 1000× 3.2/280 = 256
Now ,Molecular formula = n × Empirical formula
=) n = molecular mass / empirical mass
=) n = 256/32 =8
Hence, molecular formula of sulphur vapour = 8 × S
=) S8
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Answer:
Explanation:
Since, Density of a gas = Mass/ volume
=) 3.2gm/280 ml
Molecular mass = molar vol. × density
Since, molar volume at N.T.P = 22.4L =) 22.4×1000ml
So, molecular mass= 22.4 × 1000× 3.2/280 = 256
Now ,Molecular formula = n × Empirical formula
=) n = molecular mass / empirical mass
=) n = 256/32 =8
Hence, molecular formula of sulphur vapour = 8 × S
=) S8
please mark as brainliest answer