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280 mL of sulphur vapour at STP weighs 3.2 g. The atomicity of sulphur vapour molecule is
(Given: Atomic mass of S - 32)​

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Answered by noorishahmed
3

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Secondary School Chemistry 5 points

280ml of sulphur vapour at ntp weigh 3.2g. The molecular formula of the sulphur vapour is?

Ask for details Follow Report by Ani6948 21.07.2018

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Since, Density of a gas = Mass/ volume

=) 3.2gm/280 ml

Molecular mass = molar vol. × density

Since, molar volume at N.T.P = 22.4L =) 22.4×1000ml

So, molecular mass= 22.4 × 1000× 3.2/280 = 256

Now ,Molecular formula = n × Empirical formula

=) n = molecular mass / empirical mass

=) n = 256/32 =8

Hence, molecular formula of sulphur vapour = 8 × S

=) S8

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Answered by bhagathmanoj2905
1

Answer:

Explanation:

Since, Density of a gas = Mass/ volume

=) 3.2gm/280 ml

Molecular mass = molar vol. × density

Since, molar volume at N.T.P = 22.4L =) 22.4×1000ml

So, molecular mass= 22.4 × 1000× 3.2/280 = 256

Now ,Molecular formula = n × Empirical formula

=) n = molecular mass / empirical mass

=) n = 256/32 =8

Hence, molecular formula of sulphur vapour = 8 × S

=) S8

please mark as brainliest answer

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