2800ml of oxygen gas atSTP contains_____number of atoms of oxygen
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Answer:6.022× 10*23÷4
Explanation:
No. Of moles = Given volume/Molar volume= 2800/22400=1/8
No.of atoms = n × Avogadro × no.of atoms = 1/8 ×6.022×10*23×2=6.022×10*23÷4
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